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CLE to ZBY: distance & flight time
Cleveland (Cleveland Hopkins International Airport) → Sainyabuli (Sayaboury Airport)
8,240 mi
13,261 km · 7,160 nm
16h 37m
estimated nonstop flight time
—
time difference · heading north
See live CLE→ZBY fares Phone-only fares on this route — call free
Flight time details
8,240 miles nonstop takes roughly 16h 37m gate to gate, flying north. Add 45–90 minutes per connection if there's no nonstop service. Both airports share the same local time, so schedules read exactly as flown.
The two airports
- CLE — Cleveland Hopkins International Airport · Cleveland, United States
- ZBY — Sayaboury Airport · Sainyabuli, Laos
Distances are great-circle ("as the crow flies") — the same basis airlines use for frequent-flyer miles.
Alternate airports can cut this fare
Flying from or into a nearby airport is the #1 trick our agents use to beat online prices. Call and we'll compare every combination on one call.
Near CLE
- BKL · Burke Lakefront Airport11 mi away
- CGF · Cuyahoga County Airport22 mi away
- LNN · Willoughby Lost Nation Municipal Airport30 mi away
- AKC · Akron Fulton International Airport33 mi away
Near ZBY
- LPQ · Luang Phabang International Airport54 mi away
- NNT · Nan Airport68 mi away
- XKH · Xieng Khouang Airport96 mi away
- ODY · Oudomsay Airport101 mi away
Frequently asked questions
How far is CLE from ZBY?
The flight distance from Cleveland (CLE) to Sainyabuli (ZBY) is 8,240 miles (13,261 km, 7,160 nautical miles), measured along the great-circle route airlines actually fly.
How long is the flight from CLE to ZBY?
A nonstop flight takes about 16h 37m gate to gate. Actual time varies with winds, routing and season — eastbound transatlantic flights, for example, are usually faster than the return.
What is the cheapest way to fly from CLE to ZBY?
Compare live fares online, then call CheapoTrav — our agents have unpublished consolidator fares on CLE–ZBY that never appear on search engines, with no booking fees.