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ZSJ to CDC: distance & flight time

Sandy Lake (Sandy Lake Airport) → Cedar City (Cedar City Regional Airport)

1,421 mi
2,287 km · 1,235 nm
3h 33m
estimated nonstop flight time
-1h
time difference · heading southwest
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Flight time details

1,421 miles nonstop takes roughly 3h 33m gate to gate, flying southwest. Add 45–90 minutes per connection if there's no nonstop service. Remember to factor the 1-hour time set-back when reading arrival times on your ticket.

The two airports

Distances are great-circle ("as the crow flies") — the same basis airlines use for frequent-flyer miles.

Alternate airports can cut this fare

Flying from or into a nearby airport is the #1 trick our agents use to beat online prices. Call and we'll compare every combination on one call.

Frequently asked questions

How far is ZSJ from CDC?

The flight distance from Sandy Lake (ZSJ) to Cedar City (CDC) is 1,421 miles (2,287 km, 1,235 nautical miles), measured along the great-circle route airlines actually fly.

How long is the flight from ZSJ to CDC?

A nonstop flight takes about 3h 33m gate to gate. Actual time varies with winds, routing and season — eastbound transatlantic flights, for example, are usually faster than the return.

What is the time difference between Sandy Lake and Cedar City?

Cedar City is 1 hour behind Sandy Lake.

What is the cheapest way to fly from ZSJ to CDC?

Compare live fares online, then call CheapoTrav — our agents have unpublished consolidator fares on ZSJ–CDC that never appear on search engines, with no booking fees.
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