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ZSJ to CLE: distance & flight time

Sandy Lake (Sandy Lake Airport) → Cleveland (Cleveland Hopkins International Airport)

966 mi
1,555 km · 840 nm
2h 34m
estimated nonstop flight time
+1h
time difference · heading southeast
See live ZSJCLE fares Phone-only fares on this route — call free

Flight time details

966 miles nonstop takes roughly 2h 34m gate to gate, flying southeast. Add 45–90 minutes per connection if there's no nonstop service. Remember to factor the 1-hour time gain when reading arrival times on your ticket.

The two airports

Distances are great-circle ("as the crow flies") — the same basis airlines use for frequent-flyer miles.

Alternate airports can cut this fare

Flying from or into a nearby airport is the #1 trick our agents use to beat online prices. Call and we'll compare every combination on one call.

Frequently asked questions

How far is ZSJ from CLE?

The flight distance from Sandy Lake (ZSJ) to Cleveland (CLE) is 966 miles (1,555 km, 840 nautical miles), measured along the great-circle route airlines actually fly.

How long is the flight from ZSJ to CLE?

A nonstop flight takes about 2h 34m gate to gate. Actual time varies with winds, routing and season — eastbound transatlantic flights, for example, are usually faster than the return.

What is the time difference between Sandy Lake and Cleveland?

Cleveland is 1 hour ahead of Sandy Lake.

What is the cheapest way to fly from ZSJ to CLE?

Compare live fares online, then call CheapoTrav — our agents have unpublished consolidator fares on ZSJ–CLE that never appear on search engines, with no booking fees.
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